In a potentiometer circuit cell of emf 1.5
WebA potentiometer wire of length 1 m is connected to a driver cell of emf 3 V as shown in the figure. When a cell of 1.5 V emf is used in the secondary circuit, the balance point is found to be 60 cm. On replacing this cell and using a cell of unknown emf, the balance point shifts to 80 cm.Calculate unknown emf of the cell. WebFeb 13, 2024 · In a potentiometer circuit a cell of EMF \\( 1.5 \\mathrm{~V} \\) gives balance point at \\( 36 \\mathrm{~cm} \\) length of wire. If another cell of EMF \\( 2.5 …
In a potentiometer circuit cell of emf 1.5
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WebQ.11 In a potentiometer arrangement. E1 is the cell establishing current in primary circuit. E2 is the cell to be measured. AB is the potentiometer wire and G is a galvanometer. Which of the following are the essential condition for balance to be obtained. (A) The emf of E1 must be greater than the emf of E2. WebIn a potentiometer circuit, a cell of emf 1.5 V gives a balance point at 36 cm length of wire. If another cell of emf 2.5 V replaces the first cell, then at what length of the wire, the …
WebIf not, how will you modify the circuit? 3.23 Figure 3.34 shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5 Ω is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer ... Webthe resistor board to the negative terminal of the 1.5 V test cell, while leaving the cell connected to the potentiometer. Connect the other terminal of the resistor to the 0.1 A …
WebIn a potentiometer a cell of emf 1.5 V gives a balanced point at 32 cm length of the wire. If the cell is replaced by another cell then the balance point shifts to 65.0 cm then the emf of second cell is? Medium View solution > 3 V potentiometer used for the determination of internal resistance of a 2.4 V cell. WebFeb 9, 2024 · In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf 1.5 V is found to be 60 cm. If this cell is replaced by another cell of emf E. the length-of null point increases by 40 cm. The value of E is x/10 V. The value of x is _______. jee main 2024 1 Answer +1 vote
WebIn a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the …
WebSep 15, 2024 · In a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at wha...... high protein protein barsWebIn potentiometer experiment a cell of emf. 1.5 V. connected in the secondary circuit gives a balancing length of 165cm of the wire. If a resistance of 5 Ω is connected parallel to the … how many btu per cubic ftWebApr 22, 2024 · In a potentiometer circuit, a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of … how many btu per gallon of dieselWebIn a potentiometer circuit a cell of EMF 1.5 V gives balance point at 36 cm length of wire. If another cell of EMF 2.5 V replaces the first cell, then at what length of the wire, the balance point occurs? (1) 60 cm (2) 21.6 cm (3) 64 cm (4) 62 cm ... how many btu per kg of hydrogenWebAug 7, 2024 · In potentiometer experiment a cell of emf. 1.5V connected in the secondary circuit gives a balancing length of 165cm of the wire. If a resistance of 5 is connected … how many btu per kwhWebA potentiometer wire of length 1 m is connected to a driver cell of emf 3 V as shown in the figure. When a cell of 1×5 V emf is used in the secondary circuit, the balance point is … how many btu per gallon of propanehttp://classes.oc.edu/PhysicsLab/POTENTIO.htm how many btu per horsepower